Question
can you guys help me with these questions
Which of the following could be the units for dy/dx if y is the surface area of a tumor and x is the radius of the tumor?
square millimeters per millimeter
millimeters per centimeter
meters per second
gallons per hour
meters per radian
Which points on the curve of x2 − xy − y2 = 5 have vertical tangent lines?
(1, −2)
(2, −1) and (−2,1)
(0, squre root of 5)
There are no vertical tangents to this curve.
None of the above
Which of the following could be the units for dy/dx if y is the surface area of a tumor and x is the radius of the tumor?
square millimeters per millimeter
millimeters per centimeter
meters per second
gallons per hour
meters per radian
Which points on the curve of x2 − xy − y2 = 5 have vertical tangent lines?
(1, −2)
(2, −1) and (−2,1)
(0, squre root of 5)
There are no vertical tangents to this curve.
None of the above
Answers
surface area in m^2/radius in meters is meters
radians is arc, no units
so
meters per radian
radians is arc, no units
so
meters per radian
I assume you mean
x^2 - x y - y^2 = 5
2 x dx - x dy -y dx - 2 y dy = 0
(2y-x)dy = (2x-y)dx
dy/dx = (2x-y)/(2y-x)
slope is undefined (vertical) when
2y-x = 0
or
x = 2y
so
x^2 - x y - y^2 = 5
4y^2 -2y^2-y^2 = 5
y = +/-sqrt 5
then x = +/- 2 sqrt 5
x^2 - x y - y^2 = 5
2 x dx - x dy -y dx - 2 y dy = 0
(2y-x)dy = (2x-y)dx
dy/dx = (2x-y)/(2y-x)
slope is undefined (vertical) when
2y-x = 0
or
x = 2y
so
x^2 - x y - y^2 = 5
4y^2 -2y^2-y^2 = 5
y = +/-sqrt 5
then x = +/- 2 sqrt 5
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