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Asked by anon

use the definition of derivative to find d/dx(1/(3-x))
8 years ago

Answers

Answered by Damon
at x+h
y = 1/(3-x-h)
at x
y = 1/(3-x)

subtract
1/(3-x-h) -1/(3-x)

[(3-x) -(3-x-h)]/[(3-x-h)(3-x)]

[ h]/[ x^2-6x+xh-3h+9]

divide by h
1/[x^2-6x+9 +xh-3h]

let h --->0
1/(x-3)^2
8 years ago
Answered by Lielle
the dividing by h is confusing me. wouldn't you be left with (x^2/h)-(6x/h)+x-3+(9/h)?
8 years ago
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