Asked by sakshi
Solve the quadratic
(2x+6)(3x-1)=2
(2x+6)(3x-1)=2
Answers
Answered by
Steve
try putting things into standard form:
(2x+6)(3x-1)=2
6x^2 + 16x - 6 = 2
6x^2 + 16x - 8 = 0
or
3x^2 + 8x - 4 = 0
Now just use the quadratic formula.
(2x+6)(3x-1)=2
6x^2 + 16x - 6 = 2
6x^2 + 16x - 8 = 0
or
3x^2 + 8x - 4 = 0
Now just use the quadratic formula.
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