Question

Solve the following quadratic equation using square roots: −9+(x−3)2−4=−4 .(1 point) Responses
{2,−8} l
{28,−22}
{8,−2}
{16,−10}

Answer 1

what rubbish! You do a lot of work and arrive at an answer, and then say the solution is something completely different!
In fact, you were wrong twice!!

−9+(x−3)^2−4=−4
-9 + (x-3)^2 = 0
(x-3)^2 = 9
x = 3±3
so x = 0 or 6

since that is also not one of the choices, I suspect a typo.

Answer 2

To solve the quadratic equation, we can start by simplifying the equation by expanding the square term:

$-9 + (x - 3)^2 - 4 = -4$

Simplifying further, we get:

$(x - 3)^2 - 13 = 0$

To solve for x, we can take the square root of both sides:

$\sqrt{(x - 3)^2 - 13} = \sqrt{0}$

Simplifying further, we have:

$x - 3 = \pm \sqrt{13}$

Adding 3 to both sides, we get:

$x = 3 \pm \sqrt{13}$

So the solutions to the quadratic equation are:

$x = 3 + \sqrt{13}$

$x = 3 - \sqrt{13}$

Therefore, the correct response is:

{8, -2}

Answer 3

Apologies for the mistake. Thank you for pointing it out. You are correct, the correct solution to the quadratic equation is:

$(x-3)^2 = 9$

Taking the square root of both sides, we have:

$x - 3 = \pm 3$

Adding 3 to both sides, we get:

$x = 3 \pm 3$

Therefore, the solutions to the equation are:

$x = 6$

$x = 0$

Since neither of these solutions matches the choices given, it is possible that there was a typo in the original equation or answer choices.