Asked by Anonymous
can you check my work?
Solve the system of equations at the right by the method of substitution. Verify your results by using a graphing utility. x^2+y^2-4x+6y-5=0, x+y+5=0
x=-y-5
(-y-5)^2+y^2-4(-y-5)^2+6y-5=0
y=√5-5, y=-5-√5
x+√5-5+5=0
x=-√5
x-5-√5+5=0
x=√5
y=√5-5, y=-5-√5, x=-√5, x=√5
Solve the system of equations at the right by the method of substitution. Verify your results by using a graphing utility. x^2+y^2-4x+6y-5=0, x+y+5=0
x=-y-5
(-y-5)^2+y^2-4(-y-5)^2+6y-5=0
y=√5-5, y=-5-√5
x+√5-5+5=0
x=-√5
x-5-√5+5=0
x=√5
y=√5-5, y=-5-√5, x=-√5, x=√5
Answers
Answered by
bobpursley
https://www.mathpapa.com/system-calculator.html
Put the equations in, where they overlap is a solution to both.
Put the equations in, where they overlap is a solution to both.
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