Question

A 1000 kg car is initially at rest. If the motor does 10,000J of work on the car, what is the car’s final speed? (Neglect friction, and assume that the car is on level ground.)
Work = KE2-KE1 = KE2-0 = KE2.
KE2 = 0.5M*V^2 = 10,000 J.
500*V^2 = 10,000, V = ?.

Related Questions

Please help me on my science homework....Motor A uses 1000 joules of energy to move 200 newtons of f... A man consumes 50,000J of heat in doing his work out activities. A serving of his food provides him... A 1000 kg Toyota, initially traveling at 40 mph, collides into the rear end of a 2000 kg Cadillac, i... An electric motor exert a constant torque of 10Nm on a grindstone about the shaft is 2.0kg/m². If th...