Asked by kelsey

Initially, 0.600 mol of A is present in a 4.00-L solution.

2A[aq]->2B[aq]+C[aq]

At equilibrium, 0.200 mol of C is present. Calculate K.
Answered by bobpursley

K= [B]^2*[C}/[A]^2

A=(.6-x)/4
B= (x)
C=(x/2)=.2

use C to solve for x, then solve for the rest.
There are no AI answers yet. The ability to request AI answers is coming soon!