Asked by DRE
A SOFTBALL DIAMOND IS A SQUARE WITH SIDES OF 60 FT LONG. HOW FAR IS THIRD TO FIRST BASE. ROUND TO THE NEAREST HUNDRETH.
SO FROM THIRD TO FIRST IT WILL FORM A RIGHT TRIANGLE. THE LEGS ARE 60 TO 2ND POWER + 60 TO THE 2ND POWER. THE HYPOTENUSE IS WHAT I DON'T KNOW TO FIGURE OUT.
SO FROM THIRD TO FIRST IT WILL FORM A RIGHT TRIANGLE. THE LEGS ARE 60 TO 2ND POWER + 60 TO THE 2ND POWER. THE HYPOTENUSE IS WHAT I DON'T KNOW TO FIGURE OUT.
Answers
Answered by
Damon
60 sqrt 2
hypotenuse = sqrt (60^2+60^2)
= sqrt (2 * 60^2)
= 60 sqrt 2 = 84.85
hypotenuse = sqrt (60^2+60^2)
= sqrt (2 * 60^2)
= 60 sqrt 2 = 84.85
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