Asked by T

A baseball diamond is a square 90 feet on a side. The pitcher's mound is 60.5 feet from home. How far does the pitcher have to run to cover first? (we are using the LAW OF SINES AND COSINES)

Answers

Answered by Reiny
I see it as a simple Pythagorean problem

x^2 + 60.5^2 = 90^2
....
....
x = 66.6 feet
Answered by Reiny
OOPS, I assumed wrongly that the pitcher was halfway between home and second.

the way you state it results in a a Law of Cosine problem

x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45
= 4059.857
x = 63.72 feet
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