Asked by T
A baseball diamond is a square 90 feet on a side. The pitcher's mound is 60.5 feet from home. How far does the pitcher have to run to cover first? (we are using the LAW OF SINES AND COSINES)
Answers
Answered by
Reiny
I see it as a simple Pythagorean problem
x^2 + 60.5^2 = 90^2
....
....
x = 66.6 feet
x^2 + 60.5^2 = 90^2
....
....
x = 66.6 feet
Answered by
Reiny
OOPS, I assumed wrongly that the pitcher was halfway between home and second.
the way you state it results in a a Law of Cosine problem
x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45
= 4059.857
x = 63.72 feet
the way you state it results in a a Law of Cosine problem
x^2 = 90^ + 60.5^2 - 2(90)(60.54059.857)cos 45
= 4059.857
x = 63.72 feet
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.