Asked by Maria
kx^2-3k+5=0 find the solutions (roots)
Answers
Answered by
Damon
The way you wrote it
k x^2 = (3k-5)
x = +/- sqrt(3 - 5/k)
but I wonder if you mean
kx^2 -3kx+5
which would be
x = [3k +/- sqrt(9k^2-20k) ]/2k
k x^2 = (3k-5)
x = +/- sqrt(3 - 5/k)
but I wonder if you mean
kx^2 -3kx+5
which would be
x = [3k +/- sqrt(9k^2-20k) ]/2k
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