Asked by jasort20
i am having difficulty with this problem can someone help me.
Problem #1
Write in simplest form
(48a^5b)/(12ab^2)
this is what i get:
4a^4b^-1
Problem #2
how do i start it:
subtract. Express your result in simplest form
(12)/(z) minus (10)/(z)
Your #1 is correct, and can also be written 4a^4/b.
#2 12/z - 10/z = (12-10)*(1/z) = 2/z
canyou explain to me how do you determine to make it a 1/z
Z is a common denominator, so you can just add or subtract the numerators.
12/z - 10/z = (!2-10)/z = 2/z
The same thing is accomplished by extracting 1/z.
12/z - 10/z = (!2-10)(1/z) = 2/z
I hope this helps a little more. Thanks for asking.
thank you yes it does i appreciated...
Problem #1
Write in simplest form
(48a^5b)/(12ab^2)
this is what i get:
4a^4b^-1
Problem #2
how do i start it:
subtract. Express your result in simplest form
(12)/(z) minus (10)/(z)
Your #1 is correct, and can also be written 4a^4/b.
#2 12/z - 10/z = (12-10)*(1/z) = 2/z
canyou explain to me how do you determine to make it a 1/z
Z is a common denominator, so you can just add or subtract the numerators.
12/z - 10/z = (!2-10)/z = 2/z
The same thing is accomplished by extracting 1/z.
12/z - 10/z = (!2-10)(1/z) = 2/z
I hope this helps a little more. Thanks for asking.
thank you yes it does i appreciated...
Answers
Answered by
Anonymous
if you wanted to find the definition of 6/25-four over five what common denominator should you choose?why?
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