Asked by Ashley
Which equation is the equation of a line that passes through (-10,3) and is perpendicular to y=5x-7
A)y=5x+53*****
B)y=-1/5x-7
C)y=-1/5x+1
D)y=1/5x+5
Am I correct
Please explain
A)y=5x+53*****
B)y=-1/5x-7
C)y=-1/5x+1
D)y=1/5x+5
Am I correct
Please explain
Answers
Answered by
Reiny
the slope of the given line is 5
so the slope of the perpendicular line must be -1/5
So immediately you know your choice is wrong.
the new line must be
y-3 = (-1/5)(x+10)
y = (-1/5)x - 2 + 3
y = (-1/5)x + 1 <-------- C
what reasoning do you have to choose A ?
so the slope of the perpendicular line must be -1/5
So immediately you know your choice is wrong.
the new line must be
y-3 = (-1/5)(x+10)
y = (-1/5)x - 2 + 3
y = (-1/5)x + 1 <-------- C
what reasoning do you have to choose A ?
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