Asked by Yvonne
A is a solution of tetraoxosulphate(iv)acid.B contains 3.95g of sodium trioxocarbonate(iv) in 750cm3 of solution.if 22.70cm3 of the tetraoxosulphate(iv)acid neutralized 25.0cm3 of sodiumtrioxocarbonate(iv).calculate the concentration of
i) B in moldm-3
ii) A in moldm-3
i) B in moldm-3
ii) A in moldm-3
Answers
Answered by
DrBob222
What you REALLY mean is H2SO4 (sulfuric acid) and Na2CO3 (sodium carbonate).
H2SO4 + Na2CO3 ==> H2O + CO2 + Na2SO4
mols Na2CO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Na2SO4 to mols H2SO4. You can see that is a 1:1 ratio.
Then M H2SO4 = mols H2SO4/L H2SO4. That's A.
M of B is mols B/L B.
Note: moldm^-3 = mols/L = Molarity = M.
H2SO4 + Na2CO3 ==> H2O + CO2 + Na2SO4
mols Na2CO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Na2SO4 to mols H2SO4. You can see that is a 1:1 ratio.
Then M H2SO4 = mols H2SO4/L H2SO4. That's A.
M of B is mols B/L B.
Note: moldm^-3 = mols/L = Molarity = M.
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