Rolle's theorem cannot be applied to the function f(x) = x^1/3 on the interval [–1, 1] because...

f is not differentiable on the interval [–1, 1]

f(–1) ≠ f(1)

f is not differentiable on the interval [–1, 1] and f(–1) ≠ f(1)

Rolle's theorem can be applied to f(x) = x1/3 on the interval [–1, 1]

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