Asked by Workina
Use Rolle's Theorem to show that between any two roots of ( x-1)sinx=o there exists at least one of tanx=1-x
Answers
Answered by
oobleck
If y = (x-1) sinx, then
y' = sinx + (x-1)cosx = k sin(x+θ)
where cosθ = 1/√(1+(x-1)^2)
since k is never zero, the zeroes of y' are the same as the zeroes of y, just shifted by θ. That is, they are between the zeroes of y
Note that if
sinx + (x-1) cosx = 0
tanx + (x-1) = 0 (for cosx≠0)
y' = sinx + (x-1)cosx = k sin(x+θ)
where cosθ = 1/√(1+(x-1)^2)
since k is never zero, the zeroes of y' are the same as the zeroes of y, just shifted by θ. That is, they are between the zeroes of y
Note that if
sinx + (x-1) cosx = 0
tanx + (x-1) = 0 (for cosx≠0)
Answered by
Batirun Dejene Setegn
Student
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Maths.Assignment
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Batirun Dejene Setegn
Use Rolle'Theorm to show that between any to roots of(x_1)since=0 there exist at least one roots of tanx=1_x