Asked by Austin
Posted by Austin on Thursday, November 13, 2008 at 9:19pm.
Luis bought eight bags of candy at the store for a total price of $21.54. He bought some bags of candy that cost $2.22 each and the rest cost $3.48 each. How many bags of the $3.48 candy did Luis buy?
Responses
Math - qwerty, Thursday, November 13, 2008 at 9:23pm
A=2.22
B=3.48
A + B = 8
2.22A x 3.48B = 21.54
solve for B
Math - Austin, Thursday, November 13, 2008 at 10:08pm
I got this far, but how do I solve for B?
Math - bobpursley, Thursday, November 13, 2008 at 9:24pm
C means cheap candy bag, E means expensive candy bag.
C*2.22+E*3.48=21.54
C+E=8
Luis bought eight bags of candy at the store for a total price of $21.54. He bought some bags of candy that cost $2.22 each and the rest cost $3.48 each. How many bags of the $3.48 candy did Luis buy?
Responses
Math - qwerty, Thursday, November 13, 2008 at 9:23pm
A=2.22
B=3.48
A + B = 8
2.22A x 3.48B = 21.54
solve for B
Math - Austin, Thursday, November 13, 2008 at 10:08pm
I got this far, but how do I solve for B?
Math - bobpursley, Thursday, November 13, 2008 at 9:24pm
C means cheap candy bag, E means expensive candy bag.
C*2.22+E*3.48=21.54
C+E=8
Answers
Answered by
bobpursley
A=8-B
Put that into the other equation for A, and then solve for B.
Put that into the other equation for A, and then solve for B.
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