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Asked by Trig

Find all of the solutions between 0 and 2pi:

2sin(x)^2 = 2 + cos(x)
16 years ago

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Answered by bobpursley
I assume you meant (sin(X))^2

change the sin squared to 1-cos squared, then group the terms as in a quadratic, and solve with the quadratic equation.
16 years ago
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Find all of the solutions between 0 and 2pi:

2sin(x)^2 = 2 + cos(x)

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