Asked by Jon
Find four geometric means between 4096 and 972.
an=a1*r^n-1
a6=972*r^6-1
4096=972r^5
4.2=r^5
1.3
972(1.3)=1296
1296(1.3)=1728
1728(1.3)=2304
2304(1.3)=3072
answer=1296,1728,2304,3072
Now that I look at it, do I have the a1 and a6 values mixed up? Because in the question 4096 is the first number and 972 was the last but I just put the smaller number first instead.
an=a1*r^n-1
a6=972*r^6-1
4096=972r^5
4.2=r^5
1.3
972(1.3)=1296
1296(1.3)=1728
1728(1.3)=2304
2304(1.3)=3072
answer=1296,1728,2304,3072
Now that I look at it, do I have the a1 and a6 values mixed up? Because in the question 4096 is the first number and 972 was the last but I just put the smaller number first instead.
Answers
Answered by
Reiny
in your sequence term<sub>1</sub> = 4096
so a=4096 and
term<sub>6</sub> = ar^5 = 972
then r^5 = 972/4092
= 243/1024
= 3^5/4^5
r = 3/4
so the four geometric means would be term2, term3...
or 3072, 2304, 1728, and 1296
(notice if I multiply 1296 by 3/4 I get 972, which confirms my answer)
Don't turn the terms of a sequence around.
If │r│ > 1 the terms get larger, if │r│ < 1 the terms get smaller, which is our case.
so a=4096 and
term<sub>6</sub> = ar^5 = 972
then r^5 = 972/4092
= 243/1024
= 3^5/4^5
r = 3/4
so the four geometric means would be term2, term3...
or 3072, 2304, 1728, and 1296
(notice if I multiply 1296 by 3/4 I get 972, which confirms my answer)
Don't turn the terms of a sequence around.
If │r│ > 1 the terms get larger, if │r│ < 1 the terms get smaller, which is our case.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.