Asked by Aleesha
Write a slope-intercept equation for a line passing through the point (4,−2) that is parallel to the line 4x+7y=8. Then write a second equation for a line passing through the point (4,−2) that is perpendicular to the line 4x+7y=8.
Thank you!
Thank you!
Answers
Answered by
Damon
7y = -4 x + 8
y = -(4/7) x + /7
so m = -4/7
y = -(4/7)x + b
-2 = -(4/7)(4) + b
-14/7 + 16/7 = b
b = 2/7
so
y = -(4/7)x + 2/7
7y = -4x + 2
for the second one
m = -(-7/4) = 7/4
so
y = (7/4) x + b
now put x = 4 and y = 2 in again to find b
y = -(4/7) x + /7
so m = -4/7
y = -(4/7)x + b
-2 = -(4/7)(4) + b
-14/7 + 16/7 = b
b = 2/7
so
y = -(4/7)x + 2/7
7y = -4x + 2
for the second one
m = -(-7/4) = 7/4
so
y = (7/4) x + b
now put x = 4 and y = 2 in again to find b
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