Question

If y=tanu, u=v-(1/v), and v=lnx. What is the value of dy/dx at x=e?

Answer 1

dy/du = sec^2u
du/dv = 1 + 1/v^2
dv/dx = 1/x

dy/dx = dy/du * du/dv * dv/dx

now just crank it out. It's just algebra from here.

Answer 2

2/e

Answer 3

oh yeah just solve it