first half of flight:
u = 27.5 cos 41 = 20.75 m/s forever
Vi = 27.5 sin 41 = 18 m/s initial speed up
v = 18 - 9.81 t
at top v = 0
9.81 t = 18
t = 1.84 seconds upward
2 t = 3.68 seconds in air
3.68 seconds* 20.75 m/s = 76.3 meters range
h = 18 (1.84) -4.9(1.84)^2
15. During the opening kickoff of a college football game, the kicker kicks a football with an initial velocity of 27.5 m/s at an angle of 41° above horizontal.
I. What is the time of flight for the ball?
II. How far does it travel before hitting the ground?
III. What is the maximum height the football reaches?
2 answers
bro im bad at this