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15(5x-2)=82x+1

solve the extraneous root

3 answers

No extraneous root here.

Just a simple equation.

opss i typed it wrong

15(5^x-2)=8^2x+1

I sent it through Wolfram the way you typed it
Even Wolfram had trouble understanding what you meant:
http://www.wolframalpha.com/input/?i=solve+15(5%5Ex-2)%3D8%5E2x%2B1

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