15(5x-2)=82x+1 solve the extraneous root

  1. Given the equation 2square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.x = 6, solution is
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  2. Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is
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  3. 15(5x-2)=82x+1solve the extraneous root
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    2. Sara asked by Sara
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  4. Solve. Check for extraneous solutions.1) (/3x+7) = x-1 2) (3/2x)-3=9 Note: (/3x+7) is the square root of 3x plus 7 and
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    2. cheyanne asked by cheyanne
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  5. Solve. Check for extraneous solutions.1) (/3x+7) = x-1 2) (3/2x)-3=9 Note: (/3x+7) is the square root of 3x plus 7 and
    1. answers icon 1 answer
    2. cheyanne asked by cheyanne
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  6. Solve. Check for extraneous solutions.1) (/3x+7) = x-1 2) (3/2x)-3=9 Note: (/3x+7) is the square root of 3x plus 7 and
    1. answers icon 1 answer
    2. cheyanne asked by cheyanne
    3. views icon 624 views
  7. Solve. Check for extraneous solutions.1) (/3x+7) = x-1 2) (3/2x)-3=9 Note: (/3x+7) is the square root of 3x plus 7 and
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    2. cheyanne asked by cheyanne
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  8. Solve the equation. Identify any extraneous solutions.x = sqrt root 3x + 40
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    2. sharl asked by sharl
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  9. Given the equation 2square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution.
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  10. Solve for t:Radical(t-108) - Radical(t+186) = 6 The only possible root is t = ?. It is an extraneous root.
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    2. G asked by G
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