4*2000*g*mu=2000g*(27-0)/6
mu=27/4*6
b. torque=force*.3= 500g*mu*.3
c. change the 4 to 2.
A 2000-kg automobile with four-wheel drive and weight distributed equally on the four 60-cm diameter wheels can accelerate from 0 to 27 m/s (60 MPH) in 6 seconds.
a. Calculate the minimum coefficient of static friction between the tires and the ground. (10 pts.)
b. What torque is required on the wheels to achieve this acceleration? (10 pts.)
c. Repeat the calculation in part (a) assuming the automobile has two-wheel drive.
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