4/2 = 2 mols of CO2 for every mol of C2H6
mol of C2H6 = 2*12+6 = 30 g
mol of CO2 = 12+32 = 44 g
7500 * 2 * 44/30
2C2H6 + 7O2 --> 4CO2 + 6H20 given 7.5 X 10 to the 3rd of C2H6 how many grams of CO2 is emitted
the 7.5 x 10 to the third is 7500 what do i do to figure out the rest
2 answers
The following procedure will work these stoichiometry problems.
1. Write and balance the equation. You have that.
2. Convert What you have (C2H6) to mols. mols = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols what you have (C2H6) to mols of what you want (CO2).
4. Now convert mols of what you want (CO2 in this case) to grams. g = mols x molar mass = ?
1. Write and balance the equation. You have that.
2. Convert What you have (C2H6) to mols. mols = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols what you have (C2H6) to mols of what you want (CO2).
4. Now convert mols of what you want (CO2 in this case) to grams. g = mols x molar mass = ?