Asked by Joseph
How many mL of 0.100 M NaOH are required to neutralize (or titrate) 25.0 mL of 0.15 M H3PO4?
Answers
Answered by
bobpursley
Normalityacid*volumeacid=Normalitybase*Vb
vb=.15*3*25ml/.1=4.5*25ml
vb=.15*3*25ml/.1=4.5*25ml
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