Asked by Alisha
A gardener is making a planting in the shape of a trapezoid. It will have 41 plants in the front row, 37 in the second row, 33 in the third row, and so on. If the pattern is consistent, how many plants will there be in the last row? How many plants are there altogether?
Thank you!
Thank you!
Answers
Answered by
Steve
The nth row,
Rn = 41-4(n-1) = 45-4n
So, there are 11 rows, since 45-48 < 0
You have an AP with
a = 41
d = -4
S11 = 11/2 (2*41 + 10(-4)) = 231
Rn = 41-4(n-1) = 45-4n
So, there are 11 rows, since 45-48 < 0
You have an AP with
a = 41
d = -4
S11 = 11/2 (2*41 + 10(-4)) = 231
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