Question
It takes a force of 22 N to push a 10 kg box horizontally with a constant velocity over concrete. What is the coefficient of kinetic friction between the box and the concrete?
My guess is 10 kg/22 N = 0.4545 but I'm not sure if you have to take in account vertical forces or if 0.4545 represents the static frictional force.
My guess is 10 kg/22 N = 0.4545 but I'm not sure if you have to take in account vertical forces or if 0.4545 represents the static frictional force.
Answers
Scott
yes, gravity counts
22 / (10 * g)
22 / (10 * g)
Mike
It's not static