Asked by John
a projectile is fired vertically upward from ground level with a velocity of 1600 ft/sec. If air resistance is neglected, find its distance s(t) above ground at time t. What is its maximum height?
Answers
Answered by
Scott
s(t) = -16t^2 + 1600 t
the time of max height is on the axis on symmetry
... t = -1600 / (2 * -16)
the slope of the tangent (1st deriv) is equal to zero at max height
the time of max height is on the axis on symmetry
... t = -1600 / (2 * -16)
the slope of the tangent (1st deriv) is equal to zero at max height
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