Asked by Sandy
A projectile is fired at an upward angle of 55.0 degrees from the top of a 230m cliff with a speed of 180m/s.What will be its speed when it strikes the ground below? (Use conservation of energy.)
Answers
Answered by
drwls
You won't need to use the angle information.
What don't you understand about using conservation of energy?
Set the loss of potential energy (M g H) equal to the INCREASE in kinetic energy (1/2) M V^2. The mass will cancel out, so you don't need to know it.
Vf^2 - Vi^2 = 2 g H
H = 230 m and Vi = 180 m/s
Compute the final velocity Vf
What don't you understand about using conservation of energy?
Set the loss of potential energy (M g H) equal to the INCREASE in kinetic energy (1/2) M V^2. The mass will cancel out, so you don't need to know it.
Vf^2 - Vi^2 = 2 g H
H = 230 m and Vi = 180 m/s
Compute the final velocity Vf
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