Question

a certain force gives m1 an acceleration of 12m/s^2 the same force gives object m2 an acceleration 3.3m/s^2. wahty acceleration gives to an object having mass(A) the difference m1 and m2 (B)the sum of m1 and m2

Answer 1

F = m*a
a = F/m

F1 = m1*(12)
F2 = m2*(3.3)

F1 = F2
m1*(12) = m2*(3.3)
m1 = m2*(3.3/12)

1. m = m1-m2
a = F/(m1-m2)
a = F/[(m2*(3.3/12)-m2]
a = (m2*3.3)/[(-29/40)*m2]
a = -132/29 m/s^2 (<-- goes to negative direction)
*if m = m2-m1, a = 132/29 m/s^2

2. m = m1+m2
a = F/[(m2*(3.3/12)+m2]
a = (m2*3.3)/[(51/4)*m2]
a = 44/17 m/s^2