Asked by Shade
Find the resultant in magnitude and direction of forces 10N, 20N, 30N, 40N, acting respectively in the direction 60,120,180 and 270.
I tried drawing out the forces with the respective angles but the angles are more than 360.#confused
I tried drawing out the forces with the respective angles but the angles are more than 360.#confused
Answers
Answered by
Reiny
nothing wrong with that
you could just use the trig-vector notation
resultant = (10cos60,10sin60) + (20cos120,20sin120) + (30cos180,30sin180) + (40cos270,sin270)
= (5, 5√3) + (-10, 10√3) + (-30, 0) + (0, -40)
= ( -35, 5√3-40 ))
your sketch will confirm that
you could just use the trig-vector notation
resultant = (10cos60,10sin60) + (20cos120,20sin120) + (30cos180,30sin180) + (40cos270,sin270)
= (5, 5√3) + (-10, 10√3) + (-30, 0) + (0, -40)
= ( -35, 5√3-40 ))
your sketch will confirm that
Answered by
Musa
The two forces of 10n and 12n.calculate the resultant and the direction of two vectors.
There are no AI answers yet. The ability to request AI answers is coming soon!