Asked by Shade
Find the resultant in magnitude and direction of forces 10N, 20N, 30N, 40N, acting respectively in the direction 60,120,180 and 270.
I tried drawing out the forces with the respective angles but the angles are more than 360.#confused
I tried drawing out the forces with the respective angles but the angles are more than 360.#confused
Answers
Answered by
Reiny
nothing wrong with that
you could just use the trig-vector notation
resultant = (10cos60,10sin60) + (20cos120,20sin120) + (30cos180,30sin180) + (40cos270,sin270)
= (5, 5√3) + (-10, 10√3) + (-30, 0) + (0, -40)
= ( -35, 5√3-40 ))
your sketch will confirm that
you could just use the trig-vector notation
resultant = (10cos60,10sin60) + (20cos120,20sin120) + (30cos180,30sin180) + (40cos270,sin270)
= (5, 5√3) + (-10, 10√3) + (-30, 0) + (0, -40)
= ( -35, 5√3-40 ))
your sketch will confirm that
Answered by
Musa
The two forces of 10n and 12n.calculate the resultant and the direction of two vectors.
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