Asked by Andrea
hello, I hope you can help...
A diver accustomed to standard snorkel tubing of length 25 cm tries a self-made tube of length 8.6 m. During the attempt, what is the pressure difference (in kPa) between the external pressure on the diver's chest and the air pressure in the diver's lungs?
I've been trying rigerously with pascal's law to figure this out and I feel as though it doesn't work. I'm very stuck, please help.
A diver accustomed to standard snorkel tubing of length 25 cm tries a self-made tube of length 8.6 m. During the attempt, what is the pressure difference (in kPa) between the external pressure on the diver's chest and the air pressure in the diver's lungs?
I've been trying rigerously with pascal's law to figure this out and I feel as though it doesn't work. I'm very stuck, please help.
Answers
Answered by
Scott
hello (again)
8.6 meters is 860 cm
if you picture a stack of 860 cm cubes of water, what is the force at the bottom?
... 860 gm * g
... this is the force on one cm^2
.86 kg * 9.8 m/s^2 = f
a Pascal is one Newton per m^2
... a kPa is .001 N per cm^2
8.6 meters is 860 cm
if you picture a stack of 860 cm cubes of water, what is the force at the bottom?
... 860 gm * g
... this is the force on one cm^2
.86 kg * 9.8 m/s^2 = f
a Pascal is one Newton per m^2
... a kPa is .001 N per cm^2
Answered by
Andrea
I hadn't seen your answer the first time until after I posted this one, your reply to both helped! thanks so much scott!
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.