Asked by Niki

Suppose that at least 14.7 eV is needed to free an electron from a particular element, i.e., to ionize the atom. What is the lowest frequency photon which can accomplish this? And, what is the corresponding wavelength for that photon?

Answers

Answered by Damon
h f = 14.7 eV

lambda = c T = c/f

c about 3*10^8 m/s

Answered by Jared
You should be a teacher Damon
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