Asked by Mark
All values of theta are positive. From left to right, the first peak occurs at (pi/2,1) and the second peak occurs at (9pi/2).
A. Write the graphs equation as a cosine function.
B. Write the graphs equation as a sine function.
A. Write the graphs equation as a cosine function.
B. Write the graphs equation as a sine function.
Answers
Answered by
Steve
the period is 4?, so
f(x) = cos(x/2)
since cos(u)=1 at u=0, we have
f(x) = cos((x-?/2)/2)
see
http://www.wolframalpha.com/input/?i=cos((x-%CF%80%2F2)%2F2)+for+0+%3C%3D+x+%3C%3D+5pi
Now recall that cos(x) = sin(?/2 - u)
f(x) = cos(x/2)
since cos(u)=1 at u=0, we have
f(x) = cos((x-?/2)/2)
see
http://www.wolframalpha.com/input/?i=cos((x-%CF%80%2F2)%2F2)+for+0+%3C%3D+x+%3C%3D+5pi
Now recall that cos(x) = sin(?/2 - u)
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