Asked by aziza
What are the values of theta in the interval 0 less than or equal to theta is less than 360 that sastify the equation sin theta - 1/2 =0?
Answers
Answered by
Reiny
sinØ - 1/2 = 0
sinØ = 1/2
so Ø is in quadrants I or II
we know sin 30° = 1/2
so Ø = 30° or 150° , ( π/6 or 5π/6 radians)
sinØ = 1/2
so Ø is in quadrants I or II
we know sin 30° = 1/2
so Ø = 30° or 150° , ( π/6 or 5π/6 radians)
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