Asked by Carly
Solving system of equations by substitution.
52. {5x-2/4+1/2=3y+2/2;7y+3/3=x/2+7/3
52. {5x-2/4+1/2=3y+2/2;7y+3/3=x/2+7/3
Answers
Answered by
Steve
I assume you meant
(5x-2)/4 + 1/2 = (3y+2)/2
(7y+3/3) = x/2 + 7/3
Cleaning things up a bit, you have
5x-6y = 4
3x-42y = -8
See what you can do with that.
(5x-2)/4 + 1/2 = (3y+2)/2
(7y+3/3) = x/2 + 7/3
Cleaning things up a bit, you have
5x-6y = 4
3x-42y = -8
See what you can do with that.
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