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Asked by don

Solving Equations Containing Circular Functions : Solve
2cosx sinx + sinx = 0
when x is between 0 and 2pi
13 years ago

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Answered by Steve
sinx(2cosx+1)=0
sinx = 0 at x = 0,pi,2pi

cosx = -1/2 at x = 5pi/3,7pi/3
13 years ago
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Solving Equations Containing Circular Functions : Solve
2cosx sinx + sinx = 0
when x is between 0 and 2pi

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