Asked by don
Solving Equations Containing Circular Functions : Solve
2cosx sinx + sinx = 0
when x is between 0 and 2pi
2cosx sinx + sinx = 0
when x is between 0 and 2pi
Answers
Answered by
Steve
sinx(2cosx+1)=0
sinx = 0 at x = 0,pi,2pi
cosx = -1/2 at x = 5pi/3,7pi/3
sinx = 0 at x = 0,pi,2pi
cosx = -1/2 at x = 5pi/3,7pi/3
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