what, you can't plug in h=1 or h=6?
and online you write 5e^(-0.4h)
and online you write 5e^(-0.4h)
a) To find the number of milligrams present after 1 hour, we need to substitute h = 1 into the function D(h):
D(1) = 5e^(-0.4 * 1)
To calculate this, we need to know the value of e, which is the mathematical constant approximately equal to 2.71828.
D(1) = 5e^(-0.4)
Using a calculator or software, we can find the value of D(1) by multiplying 5 with e raised to the power of -0.4. The result is approximately 3.24150.
Therefore, after 1 hour, there will be approximately 3.24 milligrams of the drug present in the patient's bloodstream.
Next, let's move on to part (b):
b) Similarly, to find the number of milligrams present after 6 hours, we substitute h = 6 into the function D(h):
D(6) = 5e^(-0.4 * 6)
Again, we need to calculate e^(-0.4 * 6) and multiply it by 5. The value of e^(-0.4 * 6) is approximately 0.30119.
D(6) = 5 * 0.30119
Multiplying 5 with 0.30119 gives us approximately 1.50595.
Therefore, after 6 hours, there will be approximately 1.51 milligrams of the drug present in the patient's bloodstream.
So, to summarize:
a) After 1 hour: Approximately 3.24 milligrams
b) After 6 hours: Approximately 1.51 milligrams