Asked by Matt
I am unable to find the formula for this given sequence:
{2, -6/4, 24/16, -120/64, 720/256,...}
So far, I know it's at least this:
a(sub(n)) = ((-1)^(n+1))/(4^(n-1))
Basically, all I'm having trouble with is finding the pattern between the numerators. If anybody can help me with this, I would be grateful. Thanks!
{2, -6/4, 24/16, -120/64, 720/256,...}
So far, I know it's at least this:
a(sub(n)) = ((-1)^(n+1))/(4^(n-1))
Basically, all I'm having trouble with is finding the pattern between the numerators. If anybody can help me with this, I would be grateful. Thanks!
Answers
Answered by
Steve
Looks to me like
a<sub>n</sub> = (-1)^(n-1) (n+1)!/4^(n-1)
a<sub>n</sub> = (-1)^(n-1) (n+1)!/4^(n-1)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.