Asked by J
For a 0.47 M solution of LiClO compute the pH.
Hi. I am confused about this question.
I calculated the pH...but my answer is wrong. what am I doing wrong???
pH=-log(0.47)
pH=0.33
Hi. I am confused about this question.
I calculated the pH...but my answer is wrong. what am I doing wrong???
pH=-log(0.47)
pH=0.33
Answers
Answered by
DrBob222
It's wrong because you have assumed that LiClO is a strong acid. It is not. It is the salt of a strong base (LiOH) and a weak acid (HClO). As such it hydrolyzes and the weak acid part (ClO^-) does this.
......ClO^- + HOH ==> HClO + OH^-
I.....0.47.............0......0
C......-x..............x......x
E...0.47-x.............x......x
Kb for ClO^- = (Kw/Ka for HClO) = (x)(x)/0.047-x
Solve for x = (OH^-), convert to H^+, then to pH.
......ClO^- + HOH ==> HClO + OH^-
I.....0.47.............0......0
C......-x..............x......x
E...0.47-x.............x......x
Kb for ClO^- = (Kw/Ka for HClO) = (x)(x)/0.047-x
Solve for x = (OH^-), convert to H^+, then to pH.
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