The solution to inequalities is a region, not just a point. In this case, think of the graphs.
y < -x^2 is the whole inside of the downward-opening parabola with vertex at (0,0).
x^2 + y^2 < 16 is the inside of the circle of radius 4 centered at (0,0).
So, is 9+4<16? yes, the point is inside the circle.
Is -2 < -9? No. It is not inside the parabola.
How can you possibly come up with 321 as an answer? Is that x or y?
The point is not a solution of equations, because you don't have any equations; you have inequalities.
visit wolframalpha . com and enter
plot {x^2+y^2 < 16, y < -x^2}
to see the shaded region which satisfies both inequalities.