Asked by Kevin
How many volleyball games would Rana have to schedule if there were 10 teams in the league and each team played each other twice?
Answers
Answered by
Reiny
Number of games in one round
= C(10,2) = 45
but they are playing two rounds, so
total number of games = 90
= C(10,2) = 45
but they are playing two rounds, so
total number of games = 90
Answered by
anmoyes
I have no idea
Answered by
Naomi
where did you get that 10,2???? i don't get it
Answered by
Naomi
and how did you get 45???????????
Answered by
Maisie
I've got a easier way solve this question: using the table of value.
When there is 1 teams, Rana can hold 0 game;
When there is 2 teams, Rana can hold 1 game;
When there is 3 teams, Rana can hold 3 games; (Suppose there are team A, B and C, A-B, A-C, B-C, three)
When there is 4 teams, Rana can hold 6 games; (Suppose there are team A, B, C, D. A-B, A-C, A-D, B-C, B-D, C-D)
When there is 5 teams, Rana can hold 10 games;
.......
When there is 10 teams, Rana can hold 45 games.
NOTE: The players need to play with each other twice, so there will be 45*2= 90 games.
When there is 1 teams, Rana can hold 0 game;
When there is 2 teams, Rana can hold 1 game;
When there is 3 teams, Rana can hold 3 games; (Suppose there are team A, B and C, A-B, A-C, B-C, three)
When there is 4 teams, Rana can hold 6 games; (Suppose there are team A, B, C, D. A-B, A-C, A-D, B-C, B-D, C-D)
When there is 5 teams, Rana can hold 10 games;
.......
When there is 10 teams, Rana can hold 45 games.
NOTE: The players need to play with each other twice, so there will be 45*2= 90 games.
Answered by
yes
ur mom
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