Question

calculate the number of moles of cacl2 that can be obtained from 25g of limestone caco3 in the prescence of excess hydrogen chloride
CaCO3 + 2HCl ==> CaCl2 + H2O + CO2
mols CaCO3 = grams CaCO3/molar mass CaCO3 = ?
mols CaCl2 = mols CaCO3 since 1 mol CaCO3 produces 1 mol CaCl2.
Then g CaCl2 = mols CaCl2 x molar mass CaCl2 = ?
111g = 1×6.03
0.4mol
answer

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