Asked by Anonymous
(2-sin^2x)/-sinx=sinx
Is this doable. That's the answer but I can't get the l.s to equal r.s
Is this doable. That's the answer but I can't get the l.s to equal r.s
Answers
Answered by
Reiny
"I can't get the l.s to equal r.s"
If you are trying to show that it is an identity, good luck , since it is not (try it with 30° for x)
So I will assume you are solving:
(2-sin^2x)/-sinx=sinx
2 - sin^2 x = -sin^2 x
2 = 0 , which is a contradiction,
there is no solution, nor is it an identity.
If you are trying to show that it is an identity, good luck , since it is not (try it with 30° for x)
So I will assume you are solving:
(2-sin^2x)/-sinx=sinx
2 - sin^2 x = -sin^2 x
2 = 0 , which is a contradiction,
there is no solution, nor is it an identity.
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