Great. No matter which way you do it, you have to divide the region into two parts because of the boundary changes. So, the area could be either
∫[0,1] (x - x/8) dx + ∫[1,2] (1/x^2 - x/8) dx = 3/4
∫[0,1/4] (8y - y) dy + ∫[1/4,1] (1/√y - y) dy = 3/4
Sketch the given region R
and then find its area.
R is the region bounded by the curve y=1/x^2 and the lines y=x and y=x/8.
1 answer
1 answer