Asked by Manuel

sin A=-4/5;A in Quadrant 4 and csc B=-7/3;B in Quadrant 3.

What is the value of the expression cos(A-B)?
Answered by Steve
Draw your triangles. You will then see that

sinA = -4/5
cosA = 3/5

sinB = -3/7
cosB = -√40/7

Now just plug those into the formula for cos(A-B)
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