Question

i have one more question:
I know this one has to do with hess's law but i'm not sure of how to get the enthalpy of vaporization from this?

Clculate the enthalpy of vaporization of solid potassium bromide to a gas of ions, the process KBr--->K{+1}(g)+Br{-1}(g), from the following information and the enthalpy of formation of KBr(s), which is -394kJ/mol

Atomization of K: K(s)--->K(g) delta H given
Ionization of K: K(g)--> K{+1}(g)+ e(g) delta H given

VAporization of bromine: Br2(l)-->Br2(g) delta H given

Dissociation of bromine: Br2(g)-->2Br(g) delta H given

Electron attachment of bromine: Br(g)+e--->Br{-1}(g) delta H given

Answer 1

I just posted it at the original spot below.

Answer 2

thanx so much!