a. vertical forces:
fu=40+20
now, summing moments about the weighted end:
40*.5L-60*xL=0
x=20/60 so the cb is 1/3 the length from the weight end.
b. Same distance,
d1=1/2 a Tx^2
d2=1/2 4a Ty^2
same distance, so
(Tx/Ty)^2 =4
Tx/Ty=2
(1) A uniform meter rod 4ON has a piece of weight of 2ON attached to one of its end. What is the center of gravity of the system from the weight end? (2) two bodies X and Y start from rest and move with uniform acceleration of a and 4a respectively. If the bodies cover the same distance in times T(x) and T(y) find the ratio of T(x) and T(y)?
1 answer
1 answer