Question
Help: A 2 meter long, uniform bar with a mass of 46 kg is suspended from a pin so it can rotate freely. It is supported by a cable half a meter from the end. Find the tension force in the cable and the magnitude and direction of the reaction force at the wall for the bar to move
Answers
bobpursley
fw+T=46*9.8 vertical forces.
summing now about the wall..
46(9.8)*1=T*2
tension=23*9.8
fw= First equation=you do it.
summing now about the wall..
46(9.8)*1=T*2
tension=23*9.8
fw= First equation=you do it.
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